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How to get BTU value ? British Thermal Unit

How to calculate BTU value? | British Thermal Unit




BTU – British Thermal Unit

Just we need to collect the rough details according to the particular place:

1.       Area Length

2.       Area Width

3.       Area Height

4.       Maximum Persons within the Room

5.       Average outdoor Temperature


Also, we need to have two Assumptions regarding the temperatures.

Assumption 1:

Assume indoor temperature as 20 Celsius, when the air conditioning process is over (A/C).

Assumption 2:

Assume the roof temperature as 35 Celsius. This value is based on the outdoor temperature of the area and might differ from the outdoor temperature but generally, when we do the calculations, we assume it as 35 Celsius.   

 

Calculations

Calculation 1:

Total Area of walls: A

How to calculate the area of walls: - (Length * Height)*Number of walls + (Width * Height)*Number of walls

The answer should be in square meters (m2).

 

Calculation 2:

Total Area of floors: B

How to calculate the area of floors: (Length * Width)

The answer should be in square meters (m2).

 

Calculation 3:

Total Area of Roof: C

How to calculate the area of the roof: (Length * Width)

The answer should be in square meters (m2).

 

Calculation 4:

The Heat Transformation from Walls and Floors: D

The heat transformation:

= (Total Area of walls & floors) * (Constant Value) * (Cooling load temperature difference)

The constant value is equal to 2.15 for walls

                = (A+B) * 2.15 * (Average outdoor temperature – Assumption 1)

                = (D) W

The answer will be from Watt.

 

Calculation 5:

The Heat Transformation from Roof: E

The heat transformation:

                = (Total Area of Roof) * (Constant Value) * (Cooling load temperature difference)

The constant value is equal to 1.316 for the roof

                = C * 1.316 * (Assumption 2 – Assumption 1)

                = (E) W

The answer will be from Watt.

 

Calculation 6:

Internal heat by occupants: F

                = (Number of occupants * Constant Value1) + (Number of occupants * Constant Value2)

The constant value 1 is equal to 50 and Constant value 2 is equal to 80

                = (Number of occupants * 50) + (Number of occupants * 80)

                = (F) W

The answer will be from Watt.

 

Calculation 7:

Total Required Cooling Load      = D + E + F

                                                                = (D + E + F) W

 


Calculation 8:

Convert W to BTU           = (D + E + F) * Constant Value

Constant Value is equal to 3.4121

                                                = (D + E + F) * 3.4121

                                                = (Final Answer) BTU

We should use an air conditioner machine that consists of more than this value (Final Answer) BTU to remove heat.

  

Example 1:

There is a room consisting of 04 walls, a floor and a roof.

·         Length - 6m

·         Width - 5m

·         Height - 3m

·         Maximum Persons - 02

·         Outdoor Temperature - 30C

·         Assumption 1- Assume that the indoor temperature as 20 Celsius, when the air conditioning process is over.

·         Assumption 2- Assume roof temperature as 35 Celsius.

 

Calculation 1

Total area of walls            = (Length * Height)*Number of walls + (Width * Height)*Number of walls

                                          = (6*3)*2 + (5*3)*2

                                          = 36+30

                                          = 66 m2


Calculation 2

Total area of floors         = (Length * Width)

                                        = 6*5

                                        = 30 m2


Calculation 3

The area of roof               = (Length * Width)

                                         = 6*5

                                         = 30m2


Calculation 4

The heat transformation              = (Total Area of walls & floors) * (Constant Value) * (Cooling load temperature difference)

                                                     = (66+30) * 2.15 * (Average outdoor temperature – Assumption 1)

                                                     = (66+30) * 2.15 * (30-20)

                                                     = 96*2.15*10

                                                     = 2064 W


Calculation 5

The heat transformation              = (Total Area of Roof) * (Constant Value) * (Cooling load temperature difference)

                                                     = 30 * 1.316 * (35-20)

                                                     = 30 * 1.316 * 15

                                                     = 592.2 W


Calculation 6

Internal heat by occupants          = (Number of occupants * Constant Value1) + (Number of occupants * Constant Value2)

                                                     = (Number of occupants * 50) + (Number of occupants * 80)

                                                     = (2*50) + (2*80)

                                                     = 260 W

 

Calculation 7

Total Required Cooling Load        = 2064 + 592.2 + 260       

                                                       = 2916.2 W


Calculation 8

Convert W to BTU                            = (2916.2) * Constant Value

                                                          = 2916.2 * 3.4121

                                                          = 9950.367 BTU


We should use an air conditioner machine which consists of more than 9950.367 BTU to remove heat.

 


Example 2:

There is a room consisting of 04 walls, a floor, and a roof.

·         Length - 10m

·         Width - 8m

·         Height - 5m

·         Maximum Persons - 12

·         Outdoor Temperature - 33C

·         Assumption 1- Assume that the indoor temperature as 20 Celsius, when the air conditioning process is over.

·         Assumption 2- Assume roof temperature as 35 Celsius.

 

Calculation 1

Total area of walls            = (Length * Height)*Number of walls + (Width * Height)*Number of walls

                                          = (10*5)*2 + (8*5)*2

                                          = 100+80

                                          = 180 m2


Calculation 2

Total area of floors          = (Length * Width)

                                         = 10*8

                                         = 80 m2


Calculation 3

The area of roof               = (Length * Width)

                                         = 10*8

                                         = 80m2


Calculation 4

The heat transformation             = (Total Area of walls & floors) * (Constant Value) * (Cooling load temperature difference)

                                                    = (180+80) * 2.15 * (Average outdoor temperature – Assumption 1)

                                                    = (180+80) * 2.15 * (33-20)

                                                    = 260*2.15*13

                                                    = 7267 W

 

Calculation 5

The heat transformation              = (Total Area of Roof) * (Constant Value) * (Cooling load temperature difference)

                                                    = 80 * 1.316 * (35-20)

                                                    = 80 * 1.316 * 15

                                                    = 1579.2 W


Calculation 6

Internal heat by occupants          = (Number of occupants * Constant Value1) + (Number of occupants * Constant Value2)

                                                    = (Number of occupants * 50) + (Number of occupants * 80)

                                                    = (12*50) + (12*80)

                                                    = 1560 W

 

 

Calculation 7

Total Required Cooling Load        = 7267 + 1579.2 + 1560  

                                                       = 10406.2 W


Calculation 8

Convert W to BTU                            = (10406.2) * Constant Value

                                                          = 10406.2 * 3.4121

                                                          = 35506.995 BTU


We should use an air conditioner machine which consists of more than 35506.995 BTU to remove heat.

  


Example 3:

There is a factory consisting of 04 walls, a floor, a roof, and lighting resources. Additionally, we have to add the number of lights and the wattage of each one.

·         Length - 10m

·         Width - 8m

·         Height - 5m

·         Maximum Persons – 12

·         Number of bulbs – 20

·         Wattage of one bulb – 60 W

·         Outdoor Temperature - 33C

·         Assumption 1- Assume that the indoor temperature as 20 Celsius, when the air conditioning process is over.

·         Assumption 2- Assume roof temperature as 35 Celsius.

 

Calculation 1

Total area of walls            = (Length * Height)*Number of walls + (Width * Height)*Number of walls

                                          = (10*5)*2 + (8*5)*2

                                          = 100+80

                                          = 180 m2


Calculation 2

Total area of floors          = (Length * Width)

                                         = 10*8

                                         = 80 m2


Calculation 3

The area of roof               = (Length * Width)

                                         = 10*8

                                         = 80m2


Calculation 4

The heat transformation             = (Total Area of walls & floors) * (Constant Value) * (Cooling load temperature difference)

                                                    = (180+80) * 2.15 * (Average outdoor temperature – Assumption 1)

                                                    = (180+80) * 2.15 * (33-20)

                                                    = 260*2.15*13

                                                    = 7267 W

 

Calculation 5

The heat transformation              = (Total Area of Roof) * (Constant Value) * (Cooling load temperature difference)

                                                    = 80 * 1.316 * (35-20)

                                                    = 80 * 1.316 * 15

                                                    = 1579.2 W


Calculation 6

Internal heat by occupants          = (Number of occupants * Constant Value1) + (Number of occupants * Constant Value2)

                                                    = (Number of occupants * 50) + (Number of occupants * 80)

                                                    = (12*50) + (12*80)

                                                    = 1560 W


Light Calculation

Number of bulbs                       = 20

The wattage of one bulb           = 60 W

Calculation                                = Wattage of one bulb * 1.25 * Number of bulbs

                                                    = 60 * 1.25 * 20

                                                    = 1500 W

 

Calculation 7

Total Required Cooling Load        = 7267 + 1579.2 + 1560 + Light Calculation

                                                       = 7267 + 1579.2 + 1560 + 1500    

                                                       = 11906.2 W


Calculation 8

Convert W to BTU                          = (11906.2) * Constant Value

                                                        = 11906.2 * 3.4121

                                                        = 40625.145 BTU

We should use an air conditioner machine which consists of more than 40625.145 BTU to remove heat.


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